有A、B、C、D、 E、F六种物质,它们间的相互关系如右图所示 (连线表示能相互反应)。 已知A、B、C、D、E、F为六种常见化合物,它们的相互反应及...

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分析如下:D是一种金属单质,它可能是锌或铜,如果是铜.则剩下的能与铜反应的只有AgNO3,与题目不符.所以D只能是锌;A和C反应时生成一种无色气体,所以A和C是HCl和Na2CO3中的2种,而Na2CO3不与锌反应,所以,A是Na2CO3,C是HCl;而不与HCl反应的只有BaCl2,所以F是BaCl2;剩下的2种能与锌反应的就是AgNO3,也就是E,那么B就是Ca(OH)2

小故事: 很多年前, 一个爸爸和一个妈妈想休假,所以他们决定晚上去城镇。他们叫来最信任一个人来照看孩子。当保姆来的时候,他们的连个孩子已经在床上睡着了。所以保姆只是看了看孩子是否睡的好,就坐下了。
深夜,保姆觉得无聊就想去楼下看电视。但是她看不了,因为楼下没有电视(因为孩子的父母不希望他们的孩子看太多垃圾)。她就打电话给孩子的父母,问是否可以在他们的卧室看电视,当然孩子的父母同意了。
但保姆又想要最后一个请求。她问是否可以用毯子或者衣服盖住那小丑雕像,因为那使她感到很害怕。
电话沉默了一会。
(此时爸爸在和保姆通话)
他说:带孩子离开房间……
我们将会叫警察……我们从来没有什么小丑雕像。
那小丑很可能是一个从监狱逃出来的杀人犯。

电话里沉默了一会儿。

她问是否可以用毯子或者衣服盖住那小丑雕像,因为那使她感到很害怕。
电话沉默了一会。
(此时爸爸在和保姆通话)
他说:带孩子离开房间……
我们将会叫警察……我们从来没有什么小丑雕像。
那小丑很可能是一个从监狱逃出来的杀人犯。

电话里沉默了一会儿。

(正在跟保姆通话的孩子的父亲)说:带上孩子们,离开房子……我们会通知警察……我们没有一个小丑雕像……

孩子们和保姆被小丑谋杀了。

结果是,小丑是一个从监狱里逃出来的杀人犯。如果你不在5分钟内转发这个贴子,这个小丑在凌晨3点时将会拿着刀站在你的床前

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一种无色气体,就只能是CO2了,A和C就是盐酸和Na2Co3中的一种,题目说C能和D反应,D是金属,A和C中能和金属反应的只能盐酸了,所以A是Na2Co3,C是盐酸,也只有锌能和盐酸反应,所以D是锌。至于E,又要和Na2Co3反应,又要和锌反应,只能是AgNO3。现在就剩下两种了,B能和盐酸反应,所以就是Ca(OH)2,最后的F就是BaCl2,这种题目就要大胆的猜想推断,最后验证一下,如果都能通就没错了

(2010?金山区一模)A、B、C、D、E、F是初中化学常见的六种物质,它们之间的转化关系如下图所示(图中“~

(1)F是维持生命活动的气体单质,可知F为氧气,而B可以生成C,E也可生成C,且B和E之间可以反应,所以可以判断B为二氧化碳,而E为氢氧化钙,C为碳酸钙.(2)根据(1)可知,C为碳酸钙,B和D可以反应,且它们都是由两种元素组成的,所以可以知道D为水,所以可以写出它们反应的化学方程式.(3)A含有两种元素且能够生成水和二氧化碳,根据所学知识可以知道:碳氢化合物通过燃烧,即和氧气反应能够生成二氧化碳和水,而盐酸可以通过和碳酸盐反应生成二氧化碳和水,所以可以判断A为碳氢化合物或是盐酸,氧化铜可以和碳反应生成二氧化碳,可以和氢气反应生成水,所以A也可以使氧化铜,故可以知道A所含的元素为C、H或是H、Cl或Cu、O.故答案为:(1)O2 ;熟石灰;(2)CO2+Ca(OH)2═CaCO3↓+H2O; CO2+H2O═H2CO3;(3)C、H(或H、Cl或Cu、O).

(1) CO 2 (2) 纯碱 (3)复分解反应 (4)Ca(OH )2 + CO 2 ==CaCO 3 ↓+ H 2 O