C++编程(急)!
#include <iostream.h>
#include <conio.h>
#include <stdlib.h>
#include <math.h>
int number1,number2,answer,val;
class oopcalc {
public:
void calcadd();
void calcsub();
void calcdiv();
void calcmult();
void calcfartocel();
void calcceltofar();
void calcsroot();
void exitprog();
void menu();
void badinput();
private:
int add(int x, int y);
int sub(int x, int y);
int div(int x, int y);
int mult(int x, int y);
int fartocel(int x);
int celtofar(int x);
int sqroot(int x);
};
void oopcalc::calcadd()
{
cout << "The Add Function\n";
cout << "First number: ";
cin >> number1;
cout << "Second number: ";
cin >> number2;
answer = add(number1,number2);
cout << number1 << " + " << number2 << " = " << answer << endl;
cout << "Press any key to continue\n";
getch();
menu();
}
void oopcalc::calcsub()
{
cout << "The Subtract Function\n";
cout << "First number: ";
cin >> number1;
cout << "Second number: ";
cin >> number2;
answer = sub(number1,number2);
cout << number1 << " - " << number2 << " = " << answer << endl;
cout << "Press any key to continue\n";
getch();
menu();
}
void oopcalc::calcdiv()
{
cout << "The Divide Function\n";
cout << "First number: ";
cin >> number1;
cout << "Second number: ";
cin >> number2;
answer = div(number1,number2);
cout << number1 << " / " << number2 << " = " << answer << endl;
cout << "Press any key to continue\n";
getch();
menu();
}
void oopcalc::calcmult()
{
cout << "The Multiply Function\n";
cout << "First number: ";
cin >> number1;
cout << "Second number: ";
cin >> number2;
answer = mult(number1,number2);
cout << number1 << " x " << number2 << " = " << answer << endl;
cout << "Press any key to continue\n";
getch();
menu();
}
void oopcalc::calcfartocel()
{
cout << "The Farenheit to Celsius Function\n";
cout << "Enter a tempature in Farenheit: ";
cin >> number1;
answer = fartocel(number1);
cout << "The tempature in Celsius is " << answer << endl;
cout << "Press any key to continue\n";
getch();
menu();
}
void oopcalc::calcceltofar()
{
cout << "The Celsius to Farenheit Function\n";
cout << "Enter a tempature in Celsius: ";
cin >> number1;
answer = celtofar(number1);
cout << "The tempature in Farenheit is " << answer << endl;
cout << "Press any key to continue\n";
getch();
menu();
}
void oopcalc::calcsroot()
{
cout << "The Square Root Function\n";
cout << "First number: ";
cin >> number1;
answer = sqroot(number1);
cout << "The square root of " << number1 << " is " << answer << endl;
cout << "Press any key to continue\n";
getch();
menu();
}
void oopcalc::exitprog()
{
exit(-1);
}
void oopcalc::menu()
{
char input;
oopcalc a;
system("cls"); //执行系统命令：cls-清屏
cout << "==================MENU===============\n";
cout << "1: Add two numbers\n";
cout << "2: Subtract two numbers\n";
cout << "3: Divide two numbers\n";
cout << "4: Multiply two numbers\n";
cout << "5: Convert Farenheit to Celsius\n";
cout << "6: Convert Celsius to Farenheit\n";
cout << "7: Find the square root of a number\n";
cout << "8: Exit this program\n";
cout << "Choice: ";
cin >> input;
cout << "=====================================\n";
switch (input)
{
case '1': a.calcadd();
break;
case '2': a.calcsub();
break;
case '3': a.calcdiv();
break;
case '4': a.calcmult();
break;
case '5': a.calcfartocel();
break;
case '6': a.calcceltofar();
break;
case '7': a.calcsroot();
break;
case '8': a.exitprog();
break;
default: a.badinput();
}
}
void oopcalc::badinput()
{
cout << "BAD INPUT!\n";
cout << "Press any key to continue\n";
getch();
menu();
}
int oopcalc::add(int x, int y)
{
val = x + y;
return val;
}
int oopcalc::sub(int x, int y)
{
val = x - y;
return val;
}
int oopcalc::div(int x, int y)
{
val = x / y;
return val;
}
int oopcalc::mult(int x, int y)
{
val = x * y;
return val;
}
int oopcalc::fartocel(int x)
{
int cel = ((x - 32) * 5) / 9;
return cel;
}
int oopcalc::celtofar(int x)
{
int f;
f = x * 9 / 5 + 32;
return f;
}
int oopcalc::sqroot(int x)
{
int g = sqrt(x);
return g;
}
void main()
{
oopcalc s;
s.menu();
}
用c＋＋编程~
这个就是大数的加法来完成
1、线算0~9这10个数的21次方是多少，存入一个数组中
因为是大数，所以可以用二维字符数组来存储
2、做一个大数的加法
void jia(char *a,char *b,char *c)
c字符串来返回ab相加的结果
3、可以写主程序了
其实就是一个循环，用字符串的一些系统函数就可以搞定
效率不知道，你试试吧
#include #define MAXLONE_STR 100#define MAXLONE_DIG 50int getDigits(char a[],int target[]){ int i=0,k=0,index_dig=0; const int two_dig=2; while (a[i]!='\0') { if(k==2){ target[index_dig++]=(a[i-1]-48)+((a[i-2]-48)*10); k=0; } else{ i++; k++; } } //当k=1时说明尾部仅有一个数字 if(k==1) target[index_dig++]=(a[i-1]-48); return index_dig; // 返回数组长度}void main(){ char test[MAXLONE_STR]="1234567";int dig[MAXLONE_DIG];int len=getDigits(test,dig);// 输出得到的数字for (int i=0;i<len;i++) printf("%d ",dig[i]);printf("
"); }
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